新书推介:《语义网技术体系》
作者:瞿裕忠,胡伟,程龚
   XML论坛     >>W3CHINA.ORG讨论区<<     计算机科学论坛     SOAChina论坛     Blog     开放翻译计划     新浪微博  
 
  • 首页
  • 登录
  • 注册
  • 软件下载
  • 资料下载
  • 核心成员
  • 帮助
  •   Add to Google

    >> It is the theory that decides what can be observed. - Albert Einstein
    [返回] W3CHINA.ORG讨论区 - 语义网·描述逻辑·本体·RDF·OWL计算机理论与工程『 理论计算机科学 』 → [求助] 如何证明这道图论题? 查看新帖用户列表

      发表一个新主题  发表一个新投票  回复主题  (订阅本版) 您是本帖的第 7118 个阅读者浏览上一篇主题  刷新本主题   树形显示贴子 浏览下一篇主题
     * 贴子主题: [求助] 如何证明这道图论题? 举报  打印  推荐  IE收藏夹 
       本主题类别:     
     Logician 帅哥哟,离线,有人找我吗?天蝎座1984-10-28
      
      
      威望:9
      头衔:逻辑爱好者
      等级:研三(收到IBM CRL的Offer了)(版主)
      文章:1219
      积分:10357
      门派:IEEE.ORG.CN
      注册:2005/3/12

    姓名:(无权查看)
    城市:(无权查看)
    院校:(无权查看)
    给Logician发送一个短消息 把Logician加入好友 查看Logician的个人资料 搜索Logician在『 理论计算机科学 』的所有贴子 点击这里发送电邮给Logician  访问Logician的主页 引用回复这个贴子 回复这个贴子 查看Logician的博客楼主
    发贴心情 [求助] 如何证明这道图论题?

    Definition 1: Let G = <V,E> be a graph. If X is another graph and {V_x | x∈V(X)} is a partition of V into connected subsets such that, for any two vertices x,y∈X, there is a V_x-V_y edge (i.e. an edge (i,j) where i∈V_x and j∈V_y) in G if and only if (x,y)∈ E(X), we call G "an MX" and write "G = MX". If G=MX is a subgraph of another graph Y, we call X "a minor of Y".

    Definition 2: If we replace the edges of X with independent paths between their ends (so that none of these paths has an inner vertex on another path or in X), we call the graph G obtained "a subdivision of X" and write "G = TX". If G=TX is the subgraph of another graph Y, then X is "a topological minor of Y".

    Problem: show that, if Δ(X) ≤ 3, then every MX contains a TX; thus, every minor with maximum degree at most 3 of a graph is also its topological minor.


       收藏   分享  
    顶(0)
      




    ----------------------------------------------
    Three passions, simple but overwhelmingly strong, 
    have governed my life: the longing for love, the
    search for knowledge, and unbearable pity for the
    suffering of mankind.
                                - Bertrand Russell

    点击查看用户来源及管理<br>发贴IP:*.*.*.* 2005/3/20 9:19:00
     
     ljb 帅哥哟,离线,有人找我吗?
      
      
      等级:大二(研究C++)
      文章:39
      积分:271
      门派:XML.ORG.CN
      注册:2005/3/19

    姓名:(无权查看)
    城市:(无权查看)
    院校:(无权查看)
    给ljb发送一个短消息 把ljb加入好友 查看ljb的个人资料 搜索ljb在『 理论计算机科学 』的所有贴子 引用回复这个贴子 回复这个贴子 查看ljb的博客2
    发贴心情 
    such a easy problem~~~
    the only thing you need to do is to find a brance node in one brance set

    in one brance set, there is at most three node which connects other three different branch set(since \triangle(X)<=3.),call this three node output
    pick a path connects two output, and pick an other path connect the 3rd output to the previous path. the intersecting node is brance node.

    retaining these paths and edges between brance set leaves a TX.

    点击查看用户来源及管理<br>发贴IP:*.*.*.* 2005/3/20 22:00:00
     
     ljb 帅哥哟,离线,有人找我吗?
      
      
      等级:大二(研究C++)
      文章:39
      积分:271
      门派:XML.ORG.CN
      注册:2005/3/19

    姓名:(无权查看)
    城市:(无权查看)
    院校:(无权查看)
    给ljb发送一个短消息 把ljb加入好友 查看ljb的个人资料 搜索ljb在『 理论计算机科学 』的所有贴子 引用回复这个贴子 回复这个贴子 查看ljb的博客3
    发贴心情 
    I think you are reading Dxxxx's book, so i use that book's term~~~
    good book&good luck~:)
    点击查看用户来源及管理<br>发贴IP:*.*.*.* 2005/3/20 22:03:00
     
     Logician 帅哥哟,离线,有人找我吗?天蝎座1984-10-28
      
      
      威望:9
      头衔:逻辑爱好者
      等级:研三(收到IBM CRL的Offer了)(版主)
      文章:1219
      积分:10357
      门派:IEEE.ORG.CN
      注册:2005/3/12

    姓名:(无权查看)
    城市:(无权查看)
    院校:(无权查看)
    给Logician发送一个短消息 把Logician加入好友 查看Logician的个人资料 搜索Logician在『 理论计算机科学 』的所有贴子 点击这里发送电邮给Logician  访问Logician的主页 引用回复这个贴子 回复这个贴子 查看Logician的博客4
    发贴心情 
    Yep.
    That's great!
    Thank you very much!
    :)

    PS: Yes, I am reading Reinhard's book. It's really great (though some contents are a little bit too much for me......).

    以下是引用ljb在2005-3-20 22:00:08的发言:
    such a easy problem~~~
    the only thing you need to do is to find a brance node in one brance set

    in one brance set, there is at most three node which connects other three different branch set(since \triangle(X)<=3.),call this three node output
    pick a path connects two output, and pick an other path connect the 3rd output to the previous path. the intersecting node is brance node.

    retaining these paths and edges between brance set leaves a TX.


    ----------------------------------------------
    Three passions, simple but overwhelmingly strong, 
    have governed my life: the longing for love, the
    search for knowledge, and unbearable pity for the
    suffering of mankind.
                                - Bertrand Russell

    点击查看用户来源及管理<br>发贴IP:*.*.*.* 2005/3/21 12:30:00
     
     ljb 帅哥哟,离线,有人找我吗?
      
      
      等级:大二(研究C++)
      文章:39
      积分:271
      门派:XML.ORG.CN
      注册:2005/3/19

    姓名:(无权查看)
    城市:(无权查看)
    院校:(无权查看)
    给ljb发送一个短消息 把ljb加入好友 查看ljb的个人资料 搜索ljb在『 理论计算机科学 』的所有贴子 引用回复这个贴子 回复这个贴子 查看ljb的博客5
    发贴心情 
    ~~~~~~~
    some content are not that useful for CSer,such as "extremal graph theory and ramsey theory" I think,although they are really beautiful theory.
    点击查看用户来源及管理<br>发贴IP:*.*.*.* 2005/3/21 12:30:00
     
     Logician 帅哥哟,离线,有人找我吗?天蝎座1984-10-28
      
      
      威望:9
      头衔:逻辑爱好者
      等级:研三(收到IBM CRL的Offer了)(版主)
      文章:1219
      积分:10357
      门派:IEEE.ORG.CN
      注册:2005/3/12

    姓名:(无权查看)
    城市:(无权查看)
    院校:(无权查看)
    给Logician发送一个短消息 把Logician加入好友 查看Logician的个人资料 搜索Logician在『 理论计算机科学 』的所有贴子 点击这里发送电邮给Logician  访问Logician的主页 引用回复这个贴子 回复这个贴子 查看Logician的博客6
    发贴心情 
    IC.
    Thanks for your advice. :)

    以下是引用ljb在2000-1-1 9:12:08的发言:
    ~~~~~~~
    some content are not that useful for CSer,such as "extremal graph theory and ramsey theory" I think,although they are really beautiful theory.


    ----------------------------------------------
    Three passions, simple but overwhelmingly strong, 
    have governed my life: the longing for love, the
    search for knowledge, and unbearable pity for the
    suffering of mankind.
                                - Bertrand Russell

    点击查看用户来源及管理<br>发贴IP:*.*.*.* 2005/3/21 12:30:00
     
     GoogleAdSense天蝎座1984-10-28
      
      
      等级:大一新生
      文章:1
      积分:50
      门派:无门无派
      院校:未填写
      注册:2007-01-01
    给Google AdSense发送一个短消息 把Google AdSense加入好友 查看Google AdSense的个人资料 搜索Google AdSense在『 理论计算机科学 』的所有贴子 点击这里发送电邮给Google AdSense  访问Google AdSense的主页 引用回复这个贴子 回复这个贴子 查看Google AdSense的博客广告
    2024/6/17 10:39:17

    本主题贴数6,分页: [1]

    管理选项修改tag | 锁定 | 解锁 | 提升 | 删除 | 移动 | 固顶 | 总固顶 | 奖励 | 惩罚 | 发布公告
    W3C Contributing Supporter! W 3 C h i n a ( since 2003 ) 旗 下 站 点
    苏ICP备05006046号《全国人大常委会关于维护互联网安全的决定》《计算机信息网络国际联网安全保护管理办法》
    74.219ms