我们用的Tomcat 5 + Axis 1.4，采用最简单的办法，就是把java源文件改了以后，扩展名变成.jws，放在webapps目录下，变成web service。可是客户端调用的时候，凡是执行到service里创建某个类实例，就会报错，例如p.addControllerListener(new StateListener());

错误信息如下：
AxisFault
faultCode: {http://schemas.xmlsoap.org/soap/envelope/}Server.userException
faultSubcode:
faultString: java.lang.reflect.InvocationTargetException
faultActor:
faultNode:
faultDetail:
 {http://xml.apache.org/axis/}hostname:pcwin657

java.lang.reflect.InvocationTargetException
 at org.apache.axis.message.SOAPFaultBuilder.createFault(SOAPFaultBuilder.java:222)
 at org.apache.axis.message.SOAPFaultBuilder.endElement(SOAPFaultBuilder.java:129)
 at org.apache.axis.encoding.DeserializationContext.endElement(DeserializationContext.java:1087)
 at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.endElement(Unknown Source)
 at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.scanEndElement(Unknown Source)
 at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl$FragmentContentDispatcher.dispatch(Unknown Source)
 at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source)
 at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source)
 at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source)
 at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(Unknown Source)
 at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.parse(Unknown Source)
 at javax.xml.parsers.SAXParser.parse(Unknown Source)
 at org.apache.axis.encoding.DeserializationContext.parse(DeserializationContext.java:227)
 at org.apache.axis.SOAPPart.getAsSOAPEnvelope(SOAPPart.java:696)
 at org.apache.axis.Message.getSOAPEnvelope(Message.java:435)
 at org.apache.axis.handlers.soap.MustUnderstandChecker.invoke(MustUnderstandChecker.java:62)
 at org.apache.axis.client.AxisClient.invoke(AxisClient.java:206)
 at org.apache.axis.client.Call.invokeEngine(Call.java:2784)
 at org.apache.axis.client.Call.invoke(Call.java:2767)
 at org.apache.axis.client.Call.invoke(Call.java:2443)
 at org.apache.axis.client.Call.invoke(Call.java:2366)
 at org.apache.axis.client.Call.invoke(Call.java:1812)
 at VideoTransClient.main(VideoTransClient.java:27)

我的客户端代码如下：http://www.win.tue.nl/~jzhang/VideoTransClient.java
我的服务端如下：http://www.win.tue.nl/~jzhang/VideoTransmit.java

请问：我这样做是否有什么问题？web service里可以创建实例吗？我尝试了在构造函数里new一个实例，也不行。

如果我有一个java文件要发布成web service，可是它又依赖另一个java文件的类定义，我如何把两个文件都放到webservice里？谢谢

我是web service新手。请大家帮帮忙，十分感谢！

public class HelloClient{

 MyHelloClass obj;

 public String getName(){
  obj = new MyHelloClass("amosa");
  return obj.getName();}
  
 public class MyHelloClass{
   String myName;
   public MyHelloClass(String Name){myName = Name;}
   public String getName(){return "hello"+myName;}
  }
}

import org.apache.axis.client.Call;
import org.apache.axis.client.Service;
import javax.xml.namespace.QName;
import javax.xml.rpc.ServiceException;
import java.net.MalformedURLException;
import java.rmi.RemoteException;

public class SayHelloClient2
{
 public static void main(String[] args)
 {
  try
  {
    
   String endpoint =
    "http://localhost:1107/axis/HelloClient.jws";
   
   Service service = new Service();
   Call call = null;
   
   call = (Call) service.createCall();
   
   call.setOperationName(new QName(
 "http://localhost:1107/axis/HelloClient.jws",
   "getName"));

   call.setTargetEndpointAddress
   (new java.net.URL(endpoint));
   String ret = (String) call.invoke(new Object[]
                                                {});
   System.out.println("return value is " + ret);
  }
  catch (Exception ex)
  {
   ex.printStackTrace();
  }
 }
}

错误信息如下：
AxisFault
faultCode: {http://schemas.xmlsoap.org/soap/envelope/}Server.userException
faultSubcode:
faultString: java.lang.reflect.InvocationTargetException
faultActor:
faultNode:
faultDetail:
 {http://xml.apache.org/axis/}hostname:pcwin657