下面是我写的样式表：
<?xml version="1.0" encoding="GB2312"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="2.0" encoding="GB2312" indent="yes" cdata-section-elements="DataContent "  />
<xsl:template match="/">
<Result>
<xsl:for-each-group select="catalog/cd" group-by="year">
<Year>
  <xsl:attribute name="id">
    <xsl:value-of select="year" />
  </xsl:attribute>
<xsl:for-each-group select="catalog/cd" group-by="typeid">
        <Typeid >
   <xsl:attribute name="num">
    <xsl:value-of select="typeid" />
  </xsl:attribute>
<title>><xsl:value-of select="title"/></title>
        </Typeid>
</xsl:for-each-group>
</Year>
</xsl:for-each-group>
</Result>  
</xsl:template>
</xsl:stylesheet>
下面是我写的java+XSKT转换xml用的java代码，有熟悉的提点意见或者有没有更好的java方法，请不吝指教。
        String src = "d:/xslt/test.xml";
        String dest= "d:/testResult.xml";
        String xslt="d:/xslt/test.xsl";
        File xmlFile = new File(src);
        File xsltFile = new File(xslt);
        File dest2 = new File(dest);
        Source xmlSource = new StreamSource(xmlFile);
        Source xsltSource = new StreamSource(xsltFile);
        StreamResult sr = new StreamResult (dest2.toString());
        TransformerFactory transFact =
                TransformerFactory.newInstance();
        Transformer trans = transFact.newTransformer(xsltSource);
        trans.setOutputProperty("encoding", "gb2312");
        trans.transform(xmlSource, sr);

有熟悉的麻烦帮写一下能用的xslt样式表给参考下，感激涕零！